Eligibility for appearing in JEE (Advanced) is based on the performance given in JEE Main. Candidates should be out of 250,000 successful candidates.
Category |
Number of "Top" candidates |
|
|---|---|---|
OPEN |
96187 |
101250 |
OPEN-PwD |
5063 |
|
GEN-EWS |
23750 |
25000 |
GEN-EWS-PwD |
1250 |
|
OBC-NCL |
64125 |
67500 |
OBC-NCL-PwD |
3375 |
|
SC |
35625 |
37500 |
SC-PwD |
1875 |
|
ST |
17812 |
18750 |
Reservation applicable in a participating institute for admission:
Category |
Seat Reserved |
|---|---|
General category candidates |
40.5% |
GEN-EWS |
10% |
OBC-NCL |
27% |
SC |
15% |
ST |
7.5% |
PwD |
5% |
In the presence of "tied" rank/score in any category, the total number of candidates can be slightly greater than 2, 50,000.
For General or OBS-NCL category- Candidates should be born on or after 1 October 1995 (Candidate should be less than 25 years).
For SC, ST and PwD candidates- Candidates should be born on or after 1 October 1990. Five years relaxation is given to reserved categories.
The number of attempts: A candidate can attempt two times (Maximum) in consecutive years.
Candidates must pass the 12th/ Equivalent exam by any recognized Board/ as listed by NTA with compulsory subjects like Physics, Chemistry and Mathematics.
However, if the board's class 12th (or equivalent) exam result is declared after June 2018 for the academic year 2017-18. The candidates who appeared in the class 12th board examination in 2018, are eligible to appear in JEE (Advanced) 2020, provided that they fulfil other requirements to qualify for the criteria. In case, If the board's class 12th (or equivalent) exam result is declared after June 2018 for the academic year 2017-18, but the result of the candidate is awaited, will not be eligible to appear in JEE (Advanced) 2020 75% aggregate marks in 12th/equivalent exam to be eligible for JEE Main 2020 for general category student. Relaxation of 10% minimum marks for reserved category candidates.
Candidates who are confirmed to a preparatory course in IITs for the first time in 2019 are eligible to appear in JEE (Advanced) 2020.
Candidates who paid the seat acceptance fee in 2019 but did not report at any reporting centre or exit before the last round of seat allotment or if the seat was cancelled before the final round of seat allotment are eligible to appear in JEE (Advanced) 2020.
JEE Advance 2020 does not support early admission in IIT, irrespective of whether/ not, he/she has been in the program or have accepted an IIT seat by reporting to a reporting centre in the past.
Candidates whose admission was cancelled after joining any IIT are also NOT eligible to appear in JEE (Advanced) 2020.
The registration fee for JEE Advance 2020 of Indian Nationals
Indian Nationals |
Female Candidates (all categories) |
INR 1400 |
Female Candidates (all categories) |
INR 1400 |
|
All Other Candidates |
INR 1400 |
The above registration fee does not include service fee, processing fee and other charges.
Those candidates who are not citizens of India (born or naturally) and are studying at 10 + 2 level abroad or equivalent at the time of registration for JEE (Advanced) 2020 are considered as foreign nationals. The seats allotted to foreign nationals are supernumerary with a cap of 10% of the total seats in each course. Foreign nationals are outside the purview of reservation of seats under the General-EWS, OBC-NCL, SC, ST and PWD (Persons with Disability) categories mandated by the Government of India.
Identity proof of the foreign national candidate is required as a citizenship certificate/passport.
Foreign Nationals |
Candidates from SAARC countries |
USD 75 |
Candidates from Non-SAARC countries |
USD 150 |
The above registration fee does not include service fee, processing fee and other charges.
Candidates should be born on or after 1 October 1995 (Candidate should be less than 25 years). Attempts: A candidate can attempt two times (Maximum) in consecutive years.
JEE Advance 2020 does not support early admission in IIT, irrespective of whether/ not, he/she has been in the program or have accepted an IIT seat by reporting to a reporting centre in the past. Candidates whose admission was cancelled after joining any IIT are also NOT eligible to appear in JEE (Advanced) 2020.
Candidates must pass the 12th/ Equivalent exam by any recognized Board/ as listed by NTA with compulsory subjects like Physics, Chemistry, Mathematics ad a language paper.
Successful foreign candidates who are interested in giving B. Arch program conducted by IITs are required to come to IIT to write an Architecture Aptitude Test.
Foreign centres where JEE (Advanced) 2020 will be conducted
The Joint Entrance Examination is a national level engineering entrance exam held twice a year for admission of to various engineering colleges in India. The National Testing Agency conducts it.
Joint Entrance Exam is formed by two separate exams- JEE Main and JEE Advanced.
The Joint Entrance Examination (JEE) is a national-level computer-based engineering entrance exam conducted by NTA (National Test Agency) for admission to various colleges in India, such as Indian Institute of Technology, National Institute of Technology, Indian Institute of Information Technology and other Government funded technical Institutes.
NITs, IIEST, IIITs and Other-GFTIs
IITs
JEE Mains comprises of two papers, Paper-I and Paper-II. Candidates can choose either of the two. Both papers have multiple-choice questions. Paper I is for the admission in B.E./B.Tech courses. Paper-II is for the admission in B.Arch and B.Planning courses.
Candidates can choose either of the two.
JEE Main 2020 is already conducted from 1 to 6 September 2020
The result is released on 10 September on the official website of JEE Mains 2020 jeemain.nta.ac.in.
From January 2020: One additional paper (Paper III) is introduced for B. Planning students i.e. Drawing test, which will be conducted in offline mode (pen-paper based).
The validity of the result is one year.
Candidates will not get the same sets of question papers.
The normalization process is an established practice prescribed by NTA for comparing candidate scores in multi-session papers adopted in other large academic selection tests conducted in India. In simple terms, if we say. To ensure a candidate is at no loss or even get benefit from this procedure.
The NTA will rank students based on their percentile marks, which will be calculated according to a pre-determined formula. I.e.
1. If the candidate is acquiring equal marks/percentile, then among themselves merit will be determined to below sequence: · Candidate acquiring higher marks/percentile in Maths - Candidate acquiring higher marks/percentile in Physics · Candidate acquiring higher marks/percentile in chemistry · Candidate who is older
2. The final ranking will be done after the tie is resolved.
The below 5 steps to be followed to fill the registration form 1. Fill online form 2. Upload documents 3. Select the exam centre 4. Payment 5. Submit
The Exam was conducted in a total of 605 centres
The NTA will rank students based on their percentile marks, which will be calculated according to a pre-determined formula. I.e.
Over 8, 58,273 candidates have appeared in the Exam.
. JEE Main 2020 consists of 3 main subjects, namely, Mathematics, Physics and Chemistry. Paper 1 is for admission in B.E. /B. Tech. Courses- In paper
1- there are 25 questions from Mathematics, 25 from Physics and 25 from Chemistry; therefore, the total number of questions is 75. Each question will carry 4 marks, and each incorrect response gets -1 negative marking. The duration of the Exam is 3 hours (180 minutes). No negative marking is done for numerical questions. The maximum marks in the Exam are 300.Paper
2 is for admission in B. Arch - In paper 2- there are 25 questions from Mathematics, 50 from Aptitude test, 2 from Drawing Test; therefore, the total number of questions is 77. Each question will carry 4 marks, and each incorrect response gets -1 negative marking. The duration of the Exam is 3.30 hours. No negative marking is done for numerical questions. The maximum marks in the Exam are 400. Paper
3 is for admission in B. Planning courses- In paper 3- there are 25 questions from Mathematics, 50 from Aptitude test, 25 from Planning Based Objective Type MCQs, therefore, the total number of questions is 100. Each question will carry 4 marks, and each incorrect response gets -1 negative marking. The duration of the Exam is 3.30 hours (180 minutes). No negative marking is done for numerical questions. The maximum marks in the Exam are 400.
No negative marking is done for numerical questions.
There is no age criteria for the candidates in JEE Main.
NCERT is the most important textbook to prepare for JEE Main.
In JEE, the joint admission process conducted by Joint Seat Allocation Authority (JoSAA) 2020 for a total of 111 institutes for the academic year 2020-21.
To register for JEE Main counselling below procedure to be followed:-
1. Online registration
2. Choice filling and locking
3. Seat allotment
4. Seat acceptance and Fee payment
5. Document Verification
6. Reporting to the allotted college
Joint Seat Allocation Authority (JoSAA) 2020 has announced counselling, starting from 6 October 2020.
The JEE Main 2020 paper 1 result has been reported on 11 September 2020 on jeemain.nta.nic.in.
No, there is no as such dress code for JEE Mains. The only restrictions are for cap, scarf, jewellery, stoles, metallic items, etc.