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JEE Main Eligibility Criteria


    There are no age criteria for the candidates.

    As per nationality- Indian, Persons of Indian Origin, Overseas Citizens of India, Foreign Nationals and Non-resident Indians are eligible to appear in JEE Main 2020 exam.

    To be eligible for JEE Main 2020, candidates must pass the 12th/ Equivalent exam by any recognized Board/ as listed by NTA with compulsory subjects like Physics, Chemistry and Mathematics.

    75% aggregate marks in 12th/equivalent exam to be eligible for JEE Main 2020 for general category student. Relaxation of 10% minimum marks for reserved category candidates.

    Reservation applicable in a participating institute for admission:

    Category

    Seat Reserved

    GEN-EWS

    10%

    OBC-NCL

    27%

    SC

    15%

    ST

    7.5%

    PwD

    5%

  • GEN-EWS- General-Economically Weaker Section
  • OBC-NCL- Other Backward Classes- Non Creamy layer
  • SC- Scheduled Caste
  • ST- Scheduled Tribe
  • PwD- Persons with Disabilities
  • <
    The categories of disabilities are:
  • Blindness and low vision
  • Deaf and hard of hearing
  • Locomotor disability including cerebral palsy, leprosy cured, dwarfism, acid attack victims and muscular dystrophy
  • Autism, intellectual disability, specified learning disability and mental illness, and
  • Multiple disabilities from amongst persons under clauses (i) to (iv)
  • Other 'specified disabilities' mentioned in the Schedule of the RPwD Act 2016.
  • Candidates can appear for JEE Main for 3 consecutive years although the efforts of the session as two attempts in a year will be considered as one.

JEE FAQs

    Why JEE?

    The Joint Entrance Examination is a national level engineering entrance exam held twice a year for admission of to various engineering colleges in India. The National Testing Agency conducts it.

    What are the two exams that come under JEE?

    Joint Entrance Exam is formed by two separate exams- JEE Main and JEE Advanced.

    JEE is conducted by which Agency?

    The Joint Entrance Examination (JEE) is a national-level computer-based engineering entrance exam conducted by NTA (National Test Agency) for admission to various colleges in India, such as Indian Institute of Technology, National Institute of Technology, Indian Institute of Information Technology and other Government funded technical Institutes.

    What are the institutions that come under JEE Main?

    NITs, IIEST, IIITs and Other-GFTIs

    What are the Institutions comes under JEE Advance?

    IITs

    How many papers are there in JEE Main?

    JEE Mains comprises of two papers, Paper-I and Paper-II. Candidates can choose either of the two. Both papers have multiple-choice questions. Paper I is for the admission in B.E./B.Tech courses. Paper-II is for the admission in B.Arch and B.Planning courses.

    Are both papers mandatory in JEE Main?

    Candidates can choose either of the two.

    When Jain Main was conducted

    JEE Main 2020 is already conducted from 1 to 6 September 2020

    when its result was declared?

    The result is released on 10 September on the official website of JEE Mains 2020 jeemain.nta.ac.in.

    Which 3rd paper is introduced in JEE Main?

    From January 2020: One additional paper (Paper III) is introduced for B. Planning students i.e. Drawing test, which will be conducted in offline mode (pen-paper based).

    For many year result is valid?

    The validity of the result is one year.

    Will candidates get the same sets of papers?

    Candidates will not get the same sets of question papers.

    What is normalization procedure?

    The normalization process is an established practice prescribed by NTA for comparing candidate scores in multi-session papers adopted in other large academic selection tests conducted in India. In simple terms, if we say. To ensure a candidate is at no loss or even get benefit from this procedure.

    How is NTA rank calculated?

    The NTA will rank students based on their percentile marks, which will be calculated according to a pre-determined formula. I.e.

    How merit ranking is determined when there is a tie?

    1. If the candidate is acquiring equal marks/percentile, then among themselves merit will be determined to below sequence: · Candidate acquiring higher marks/percentile in Maths - Candidate acquiring higher marks/percentile in Physics · Candidate acquiring higher marks/percentile in chemistry · Candidate who is older
    2. The final ranking will be done after the tie is resolved.

    What is the process of JEE Main registration?

    The below 5 steps to be followed to fill the registration form 1. Fill online form 2. Upload documents 3. Select the exam centre 4. Payment 5. Submit

    In how many centres, the Exam was conducted?

    The Exam was conducted in a total of 605 centres

    How is NTA rank calculated?

    The NTA will rank students based on their percentile marks, which will be calculated according to a pre-determined formula. I.e.

    How many candidates appeared in the Exam?

    Over 8, 58,273 candidates have appeared in the Exam.

    What is the pattern of the Exam?

    . JEE Main 2020 consists of 3 main subjects, namely, Mathematics, Physics and Chemistry. Paper 1 is for admission in B.E. /B. Tech. Courses- In paper
    1- there are 25 questions from Mathematics, 25 from Physics and 25 from Chemistry; therefore, the total number of questions is 75. Each question will carry 4 marks, and each incorrect response gets -1 negative marking. The duration of the Exam is 3 hours (180 minutes). No negative marking is done for numerical questions. The maximum marks in the Exam are 300.Paper
    2 is for admission in B. Arch - In paper 2- there are 25 questions from Mathematics, 50 from Aptitude test, 2 from Drawing Test; therefore, the total number of questions is 77. Each question will carry 4 marks, and each incorrect response gets -1 negative marking. The duration of the Exam is 3.30 hours. No negative marking is done for numerical questions. The maximum marks in the Exam are 400. Paper
    3 is for admission in B. Planning courses- In paper 3- there are 25 questions from Mathematics, 50 from Aptitude test, 25 from Planning Based Objective Type MCQs, therefore, the total number of questions is 100. Each question will carry 4 marks, and each incorrect response gets -1 negative marking. The duration of the Exam is 3.30 hours (180 minutes). No negative marking is done for numerical questions. The maximum marks in the Exam are 400.

    is there any negative marking for the numerical question?

    No negative marking is done for numerical questions.

    is there any age criteria set for JEE - Main?

    There is no age criteria for the candidates in JEE Main.

    Is NCERT important for JEE Main?

    NCERT is the most important textbook to prepare for JEE Main.

    Who conducts JEE counselling?

    In JEE, the joint admission process conducted by Joint Seat Allocation Authority (JoSAA) 2020 for a total of 111 institutes for the academic year 2020-21.

    How to register for JEE Main counselling?

    To register for JEE Main counselling below procedure to be followed:-
    1. Online registration
    2. Choice filling and locking
    3. Seat allotment
    4. Seat acceptance and Fee payment
    5. Document Verification
    6. Reporting to the allotted college

    Who announced the dates of counselling and when?

    Joint Seat Allocation Authority (JoSAA) 2020 has announced counselling, starting from 6 October 2020.

    When the result was declared?

    The JEE Main 2020 paper 1 result has been reported on 11 September 2020 on jeemain.nta.nic.in.

    Any dress code for JEE Main?

    No, there is no as such dress code for JEE Mains. The only restrictions are for cap, scarf, jewellery, stoles, metallic items, etc.